Q94 / 160 · AP EAMCET 2020 (18 Sep Shift 1) · Mathematics
\(\frac{1-\cos (2 x)+\sin (x)}{\sin (2 x)+\cos (x)}=\)
- A\(\sin (x)\)
- B\(\cos (x)\)
- Correct answerC\(\tan (x)\)
- D\(\operatorname{cosec}(x)\)
Solution
\(\begin{aligned}
& \frac{1-\cos 2 x+\sin x}{\sin 2 x+\cos x}=\frac{2 \sin ^2 x+\sin x}{2 \sin x \cos x+\cos x} \\
& \frac{\sin x(2 \sin x+1)}{\cos x(2 \sin x+1)}=\tan x.
\end{aligned}\)
Hence, the correct answer is option: 'C'.