Q95 / 160 · AP EAMCET 2020 (18 Sep Shift 1) · Mathematics

Find \(\sum_{t=1}^{39} f(t)\) if \(f: \mathbf{R} \rightarrow \mathbf{R}\) is defined as \(f(x+y)=f(x)+f(y), x, y \in \mathbf{R}\) and \(f(\mathrm{I})=7\)

  • A
    5187
  • Correct answer
    B
    5460
  • C
    5740
  • D
    5407

Solution

It is given that, \(f(x+y)=f(x)+f(y)\) and \(\begin{aligned} & f(1)=7 \\ & f(x)=7 x \end{aligned}\) \(\therefore \quad f(x)=7 x\) So, \(\begin{aligned} \sum_{t=1}^{39} f(t) & =7[1+2+3+\ldots+39] \\ & =7 \times \frac{39 \times 40}{2}=5460. \end{aligned}\)

Hence, the correct answer is option: 'B'.

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