0.1 mol of the following given antiviral compound
\((\mathrm{P})\) will weigh ________ \(\times 10^{-1} \mathrm{~g}\)

(Given : molar mass in \(\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14\), \(\mathrm{O}: 16, \mathrm{~F}: 19, \mathrm{I}: 127)\)

Solution

\(\begin{aligned} & \text {Molar mass }=372 \mathrm{gm} \\ & \therefore 0.1 \text { mole has }=372 \times 10^{-1} \mathrm{gm}\end{aligned}\)

Hence, the correct answer is 372.