Q1 / 75 · JEE Main 2026 (04 April Shift 1) · Chemistry
Number of moles and number of molecules in $1.4187$ L of $SO_2$ at STP respectively are:
- A$0.1266; 3.812 \times 10^{22}$
- Correct answerB$0.0633; 3.812 \times 10^{22}$
- C$0.1266; 7.6238 \times 10^{22}$
- D$0.0633; 7.6238 \times 10^{22}$
Solution
Volume of $SO_2$ at STP $= 1.4187$ L
Molar volume of an ideal gas at STP is approximately $22.414$ L.
Number of moles $n = \dfrac{\text{Volume}}{\text{Molar Volume}} = \dfrac{1.4187}{22.414} = 0.0633$
Number of molecules $= n \times N_A$
Number of molecules $= 0.0633 \times 6.022 \times 10^{23} = 3.812 \times 10^{22}$
Answer: $0.0633; 3.812 \times 10^{22}$
Molar volume of an ideal gas at STP is approximately $22.414$ L.
Number of moles $n = \dfrac{\text{Volume}}{\text{Molar Volume}} = \dfrac{1.4187}{22.414} = 0.0633$
Number of molecules $= n \times N_A$
Number of molecules $= 0.0633 \times 6.022 \times 10^{23} = 3.812 \times 10^{22}$
Answer: $0.0633; 3.812 \times 10^{22}$
Hence, the correct answer is option: 'B'.