Q67 / 90 · JEE Main 2023 (10 Apr Shift 2) · Physics

Young’s moduli of the material of wires A and B are in the ratio of 1 : 4, while its area of cross sections are in the ratio of 1 : 3. If the same amount of load is applied to both the wires, the amount of elongation produced in the wires A and B will be in the ratio of [Assume length of wires A and B are same]

  • Correct answer
    A
    12 : 1
  • B
    1 : 36 
  • C
    36 : 1
  • D
    1 : 12

Solution

The formula to calculate the elongation of a metallic wire because of the application of a load can be written as

ΔL=FLAY   ...1

The ratio of the elongations for both the wires is, then, calculated as follows-

∆L1∆L2=FLA1Y1FLA2Y2= A2Y2A1Y1=31×41=121

Hence, the correct answer is option: 'A'.

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