Q94 / 200 · NEET 2007 · Chemistry
Which one of the following on treatment with $50 \%$ aqueous sodium hydroxide yields the corresponding alcohol and acid?
- A$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}$
- B$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CHO}$
- C
- Correct answerD$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CHO}$
Solution
According to Cannizzaro's reaction.
$2 \mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}+\mathrm{NaOH} \stackrel{50 \% \mathrm{NaOH}}{\rightleftharpoons} \mathrm{C}_6 \mathrm{H}_5 \mathrm{COONa}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{OH}$
Related Theory
Aldehydes containing no $\alpha$-hydrogen atom on warming with $50 \% \mathrm{NaOH}$ or $\mathrm{KOH}$ undergo disproportionation i.e. self oxidation reduction known as Cannizzaro's reaction.
Caution
Aldehydes that contains alpha hydrogen atoms are not involved in Cannizzaro reaction.
Hence, the correct answer is option: 'D'.