Q25 / 160 · TS EAMCET 2016 · Chemistry

Which one of the following is correct plot of $\Lambda_{\mathrm{m}}\left(\right.$ in $\mathrm{scm}^2 \mathrm{~mol}^{-1}$ ) and $\sqrt{C}$ (in $\mathrm{mol} / \mathrm{L}^{1 / 2}$ ) for KCl solution? $\left(y=\Lambda_m ; x-\sqrt{C}\right)$

  • A
    Figure
  • Correct answer
    B
    Figure
  • C
    Figure
  • D
    Figure

Solution

Molar conductivity is given as $\Lambda_m=\Lambda_m^{\circ}-A \sqrt{C}$ Thus, as the $\sqrt{C}$ increases , $\Lambda_m$ decreases.

Hence, the correct answer is option: 'B'.

Relevant Questions