Which of the following solutions exhibits lowest value of boiling point elevation assuming complete dissociation?

\begin{array}{|l|l|c|} \hline & \multicolumn{1}{|c|}{ Solution } & \begin{array}{c} Moles of particles in \\ \mathbf{1} \mathbf{~ k g ~ s o l u t i o n ~} \end{array} \\ \hline (A) & 0.1 \mathrm{~m} \mathrm{AlCl}_3 & 0.4 \\ \hline (B) & 0.01 \mathrm{~m} \mathrm{AlCl}_2 & 0.03 \\ \hline (C) & 1 \mathrm{~m} \mathrm{KCl} & 2 \\ \hline (D) & 0.5 \mathrm{~m} \mathrm{NaCl} & 1 \\ \hline \end{array} $0.01 \mathrm{~m} \mathrm{MgCl}_2$ solution has minimum number of particles in solution, so it shows the lowest value of boiling point elevation.