Q15 / 150 · MHT CET 2026 (20 April Shift 2) · Chemistry
Find the osmotic pressure of 0.01 M solution at 25 °C $(R = 0.0821\ \text{L atm mol}^{-1}\text{K}^{-1})$
- A$0.201$ atm
- Correct answerB$0.245$ atm
- C$0.082$ atm
- D$0.41$ atm
Solution
The osmotic pressure $\pi$ is given by the formula:
$\pi = CRT$
Here, $C = 0.01$ M, $T = 25^\circ\text{C} = 298$ K, and $R = 0.0821$ L atm mol$^{-1}$ K$^{-1}$.
$\pi = 0.01 \times 0.0821 \times 298$
$\pi = 0.244658$ atm $\approx 0.245$ atm
Answer: $0.245$ atm
$\pi = CRT$
Here, $C = 0.01$ M, $T = 25^\circ\text{C} = 298$ K, and $R = 0.0821$ L atm mol$^{-1}$ K$^{-1}$.
$\pi = 0.01 \times 0.0821 \times 298$
$\pi = 0.244658$ atm $\approx 0.245$ atm
Answer: $0.245$ atm
Hence, the correct answer is option: 'B'.