Q74 / 180 · NEET 2020 (Phase 1) · Chemistry
Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?
- A
- B
- C
- Correct answerD
Solution
\(\begin{aligned} & \mathrm{I}^{-}<\mathrm{Br}^{-}<\mathrm{S}^{2-}<\mathrm{SCN}^{-}(\mathrm{S}-\text { bonded })<\mathrm{Cl}^{-}<\mathrm{NO}_3^{-}<\mathrm{N}_3^{-}<\mathrm{F}^{-}<\mathrm{OH}^{-}<\mathrm{C}_2 \mathrm{O}_4{ }^{2-}<\mathrm{H}_2 \mathrm{O}<\mathrm{NCS}^{-}(\mathrm{N}-\text { bonded })< \\ & \mathrm{CH}_3 \mathrm{CN}<\text { py (pyridine) }<\mathrm{NH}_3<\text { en (ethylenediamine) }<\text { bipy }\left(2,2^{\prime} \text {-bipyridine) }<\text { phen (1,10-phenanthroline) }\right. \\ & <\mathrm{NO}_2^{-}\left(\mathrm{N} \text {-bonded) }<\mathrm{PPh}_3 \text { (Triphenylphosphine) }<\mathrm{CN}^{-}<\mathrm{CO}\right.\end{aligned}\)
Hence, the correct answer is option: 'D'.