Q34 / 150 · MHT CET 2024 (03 May Shift 1) · Chemistry
Which from the following statements is correct for aqueous solution of $6 \mathrm{gL}^{-1}$ urea and $17 \cdot 12 \mathrm{~g} \mathrm{~L}^{-1}$ of sucrose?
[Molar mass of urea $=60 \mathrm{~g} \mathrm{~mol}^{-1}$
Molar mass of sucrose $=342 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
- AOsmotic pressure exhibited by urea solution is lower than that of sucrose solution.
- Correct answerBUrea solution is hypertonic to sucrose solution,
- CThese solutions are isotonic.
- DOn doubling the concentration of sucrose solution it becomes hypertonic to urea solution.
Solution
$\mathrm{M}_{\text {urea }}=\frac{\text { mass of urea in solution }}{\text { molar mass of urea } \times \text { volume of solution (in } L \text { ) }}$
$=\frac{\frac{6 \mathrm{~g}}{60 \mathrm{~g} \mathrm{~mol}^{-1}}}{1 \text { Litre }}=0.1 \mathrm{~mol} \mathrm{~L}^{-1}$
$\mathrm{M}_{\text {sucrose }}=\frac{\text { mass of sucrose in solution }}{\text { molar mass of sucrose } \times \text { volume of solution (in } L \text { ) }}$
$=\frac{\frac{17.12 \mathrm{~g}}{342 \mathrm{~g} \mathrm{~mol}^{-1}}}{1 \mathrm{Litre}^2}=0.05 \mathrm{~mol} \mathrm{~L}^{-1}$
Urea has higher solute concentration $(0.1 \mathrm{M})$ than sucrose ( 0.05 M ).
Thus, urea solution is hypertonic to sucrose.
Hence, the correct answer is option: 'B'.