Q80 / 84 · JEE Advanced 2010 (Paper 1) · Physics

When two progressive waves $y_1=4 \sin (2 x-6 t) \quad$ and $y_2=3 \sin \left(2 x-6 t-\frac{\pi}{2}\right) \quad$ are superimposed, the amplitude of the resultant wave is

Correct answer: 5

Solution

Phase difference between the two waves is $90^{\circ}$. Amplitudes are added by vector method. $\therefore$ Answer is 5 .

Hence, the correct answer is 5.

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