When photon of energy $4.0 \mathrm{eV}$ strikes the surface of a metal $A$, the elected photoelectrons have maximum kinetic energy $T_A \mathrm{eV}$ and de-Broglie wavelength ${\lambda }_A$. The maximum kinetic energy of photoelectron liberated from another metal $B$ by photon of energy $4.50 \mathrm{eV}$ is $T_B=\left(T_A-1.50\right) \mathrm{eV}$. If the de-Broglie wavelength of these photoelectrons ${\lambda }_B=2{\lambda }_A$, then choose the correct statement(s).

• A

  The work function of $A$ is $1.50 \mathrm{eV}$
• Correct answer
  B

  The work function of $B$ is $4.0 \mathrm{eV}$
• C

  $T_A=3.2 \mathrm{eV}$
• D

  All of the above

Hence, the correct answer is option: 'B'.