Q100 / 100 · BITSAT 2023 (Memory Based Paper 1) · Physics

The energy levels of an atom is shown is figure. Which one of these transitions will result in the emission of a photon of wavelength $124.1 \mathrm{~nm}$ ? Given $\left(\mathrm{h}=6.62 \times 10^{-34} \mathrm{Js}\right)$
Figure

  • A
    B
  • B
    A
  • C
    C
  • Correct answer
    D
    D

Solution

As $\mathrm{E}(\mathrm{eV})=\frac{1240}{\lambda(\mathrm{nm})}=\frac{1240}{124.1} \simeq 10 \mathrm{eV}$
Only is transition (D), the energy gap is $10 \mathrm{eV}$ So, option (d) is correct

Hence, the correct answer is option: 'D'.

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