When $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHCl}_2$ is treated with $\mathrm{NaNH}_2$, the product formed is:

• A

  $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$
• Correct answer
  B

  $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$
• C

  
  
• D

  
  

Hence, the correct answer is option: 'B'.