Q41 / 180 · JIPMER 2015 · Chemistry
What percentage of $\beta$-D-(+)-glucopyranose is found at equilibrium in the aqueous solution?
- Correct answerA64\%
- B$36 \%$
- C$\approx 100 \%$
- D$\approx 50 \%$
Solution
Ordinary glucose is $\alpha$-glucose, with a fresh aqueous solution has specific rotation, $[\alpha]_D=+110^{\circ}$. On keeping the solution for sometimes, $\alpha$-glucose slowly changes into an equilibrium mixture of $\alpha$-glucose (36\%) and $\beta$-glucose ( $64 \%$ ) and the mixture has specific rotation $+52.5^{\circ}$
Hence, the correct answer is option: 'A'.