Q41 / 150 · MHT CET 2025 (26 Apr Shift 2) · Chemistry

What is the value of spin only magnetic moment for $\mathrm{Cu}^{2+}$ in BM ?

  • A
    2.84
  • B
    3.87
  • Correct answer
    C
    1.73
  • D
    0.0

Solution

The spin-only magnetic moment of $\mathrm{Cu}^{2+}$ ($Z = 29$) is determined from its $3d^9$ configuration, where nine electrons occupy the d-orbitals with one unpaired electron remaining.

Applying the spin-only magnetic moment formula $\mu_s = \sqrt{n(n+2)}$ BM with $n = 1$ yields $\mu_s = \sqrt{3} \approx 1.73$ BM.

This corresponds to option C.

Hence, the correct answer is option: 'C'.

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