Q13 / 150 · MHT CET 2026 (19 April Shift 1) · Chemistry
What is the highest possible oxidation state exhibited by manganese ?
- A$+8$
- B$+5$
- C$+6$
- Correct answerD$+7$
Solution
The atomic number of manganese (Mn) is $25$.
Its electronic configuration is $[Ar] 3d^{5} 4s^{2}$.
The highest oxidation state is achieved when all the valence electrons (both $4s$ and $3d$ electrons) participate in bonding.
Total number of valence electrons $= 5 + 2 = 7$.
Therefore, the highest possible oxidation state exhibited by manganese is $+7$, which is seen in compounds like $KMnO_{4}$ and $Mn_{2}O_{7}$.
Answer: $+7$
Its electronic configuration is $[Ar] 3d^{5} 4s^{2}$.
The highest oxidation state is achieved when all the valence electrons (both $4s$ and $3d$ electrons) participate in bonding.
Total number of valence electrons $= 5 + 2 = 7$.
Therefore, the highest possible oxidation state exhibited by manganese is $+7$, which is seen in compounds like $KMnO_{4}$ and $Mn_{2}O_{7}$.
Answer: $+7$
Hence, the correct answer is option: 'D'.