Q49 / 150 · MHT CET 2020 (15 Oct Shift 1) · Chemistry
What is the value of $\Delta \mathrm{H}^{\circ}$ for the formation of ethanol from ethene gas and liquid water from following data?
(i) $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}_{(1)}+3 \mathrm{O}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{CO}_{2(\mathrm{~g})}+3 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})} \Delta \mathrm{H}^{\circ}=-1368 \mathrm{~kJ}$
(ii) $\mathrm{C}_{2} \mathrm{H}_{4(\mathrm{~g})}+3 \mathrm{O}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})} \Delta \mathrm{H}^{\circ}=1410 \mathrm{~kJ}$
- A$-1326 \cdot 0 \mathrm{~kJ}$
- B$-4188 \cdot 0 \mathrm{~kJ}$
- Correct answerC$-42 \cdot 0 \mathrm{~kJ}$
- D$-2778 \cdot 0 \mathrm{~kJ}$
Solution
Subtract equation (i) from equation (ii) $\therefore \quad \Delta H^{0}=1410-1368=42 \mathrm{~kJ}$
Hence, the correct answer is option: 'C'.