Q40 / 220 · NTA Abhyas (NEET) 2020 · Chemistry · Ionic Equilibrium

What is the $p H$ of the $N a O H$ solution when 0.04 gm of it dissolved in water and made to 100 ml solution?

A
2
B
1
C
13
Correct answer
D
12

Solution

[O H^{-}] = \frac{0.04}{40} \times \frac{1000}{100} = 10^{- 2}

p O H = 2, p H = 14 - 2 = 12.

Hence, the correct answer is option: 'D'.

More Ionic Equilibrium Questions

CH 3 NH 2 0.12 mole , pK b = 3.3 is added to 0.08 m o l e s of H C l and the solution is diluted to one litre, resulting p H of solution is:
Solubility product K s p of saturated P b C l 2 in water is 1.8 × 10 - 4 m o l 3 d m - 9 . What is the concentration of P b 2 + in the solut
A buffer solution is prepared by mixing 20 ml of 0.1 M C H 3 C O O H and 40 ml of 0.5 M C H 3 C O O N a and then diluted by adding 100 ml of
Solid B a ( N O 3 ) 2 is gradually dissolved in a 1.0 × 1 0 - 4 M N a 2 C O 3 solution. At what concentration of B a 2 + will a precipitate
The solubility product of A g 2 C r O 4 is 32 × 10 - 12 . What is the concentration of C r O 4 - ions in that solution?
At 25 ° C the pH of water is 7. When temperature of water is increased to 70 ° C than pH of water and nature of water is