Q36 / 150 · MHT CET 2025 (23 Apr Shift 1) · Chemistry

What is the molar mass of third homologue of alkane series?

  • A
    $40 \mathrm{~g} \mathrm{~mol}^{-1}$
  • B
    $58 \mathrm{~g} \mathrm{~mol}^{-1}$
  • Correct answer
    C
    $44 \mathrm{~g} \mathrm{~mol}^{-1}$
  • D
    $46 \mathrm{~g} \mathrm{~mol}^{-1}$

Solution

The third homologue of the alkane series has the molecular formula $C_3H_8$. Its molar mass is calculated as $3 \times 12 + 8 \times 1 = 44$ g/mol.

Final answer: $\boxed{\text{C}}$

Hence, the correct answer is option: 'C'.

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