Q59 / 180 · NEET 2013 (Karnataka) · Chemistry
What is the density of $\mathrm{N}_2$ at $227^{\circ} \mathrm{C}$ and $5.00 \mathrm{~atm}$ pressure? $\left(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1}\right.$ $\left.\mathrm{mol}^{-1}\right)$
- A$1.40 \mathrm{~g} / \mathrm{ml}$
- B$2.81 \mathrm{~g} / \mathrm{ml}$
- Correct answerC$3.41 \mathrm{~g} / \mathrm{ml}$
- D$0.29 \mathrm{~g} / \mathrm{ml}$
Solution
$$
\begin{aligned}
\mathrm{pV} & =n \mathrm{RT} \\
\mathrm{P} & =\frac{\mathrm{m}}{\mathrm{M}} \times \frac{\mathrm{RT}}{\mathrm{V}} \\
& =\frac{5 \times 28}{0.0821 \times 500}=3.41 \mathrm{~g} / \mathrm{mL}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.