Q38 / 102 · NTA Abhyas (JEE Main) 2020 · Chemistry · Ionic Equilibrium

What is H+ in a solution that is 0.01 M in HCN and 0.02 M in NaCN?
br /> (Kafor HCN=6.2×10-10)

  • A
    3.1×1010
  • B
    6.2×105
  • C
    6.2×10-10
  • Correct answer
    D
    3.1×10-10

Solution

K a  =  H +   CN − HCN
6.2×10-10=[H+] [0.02][0.01]
NaCN = CN − due to common ion effect
H+=6.2×10-10×0.010.02=3.1×10-10

Hence, the correct answer is option: 'D'.

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