Q1 / 102 · NTA Abhyas (JEE Main) 2020 · Chemistry · Ionic Equilibrium

Find out the percentage dissociation of an acid having conc. of $10 M$ and dissociation constant $1.0 \times 1 0^{- 3}$ .

A
0.1
B
0.5
Correct answer
C
1.0
D
2.0

Solution

α = \sqrt{\frac{1 0^{- 3}}{10}} = 1 0^{- 2}

% α = 1 0^{- 2} \times 100 = 1 %

Hence, the correct answer is option: 'C'.

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