Water falls from a 40 m high dam at the rate of 9×10^4 kg per hour. Fifty percentage of gravitational potential energy can be converted into…

Question

Water falls from a 40 m high dam at the rate of 9×10^4 kg per hour. Fifty percentage of gravitational potential energy can be converted into electrical energy. Using this hydro electric energy number of 100 W lamps, that can be lit, is (Take g=10 ms^(-2))

MARKS Content Team · Accepted Answer

Correct answer: (B) 50. Since 50% efficiency is given, half of the energy of the falling water will be used by the bulbs. Therefore, 1/2(∆mgh)/(Δt)=n×P⇒1/2×(9×10^4)/3600×10×40=100n⇒n=50

Water falls from a $40 m$ high dam at the rate of $9 \times 10^{4} kg$ per hour. Fifty percentage of gravitational potential energy can be converted into electrical energy. Using this hydro electric energy number of $100 W$ lamps, that can be lit, is
(Take $g = 10 {ms}^{- 2}$ )

Solution

Relevant Questions

Water falls from a 40 m high dam at the rate of 9×104 kg per hour. Fifty percentage of gravitational potential energy can be converted into electrical energy. Using this hydro electric energy number of 100 W lamps, that can be lit, is(Take g=10 ms-2)

Solution

Relevant Questions

Water falls from a $40 m$ high dam at the rate of $9 \times 10^{4} kg$ per hour. Fifty percentage of gravitational potential energy can be converted into electrical energy. Using this hydro electric energy number of $100 W$ lamps, that can be lit, is
(Take $g = 10 {ms}^{- 2}$ )