Q51 / 199 · NEET 2008 (Mains) · Chemistry

Volume occupied by one molecule of water (density $\left.=1 \mathrm{~g} \mathrm{~cm}^{-3}\right)$ is

  • A
    $5.5 \times 10^{-23} \mathrm{~cm}^3$
  • B
    $9.0 \times 10^{-23} \mathrm{~cm}^3$
  • C
    $6.023 \times 10^{-23} \mathrm{~cm}^3$
  • Correct answer
    D
    $3.0 \times 10^{-23} \mathrm{~cm}^3$

Solution

Volume of 1 molecule of $\mathrm{H}_2 \mathrm{O}=\frac{18 \mathrm{~g}}{6.02 \times 10^{23} \times 1 \mathrm{~g} / \mathrm{cc}}$ $$ \cong 3.0 \times 10^{-23} \mathrm{~cm}^3 $$

Hence, the correct answer is option: 'D'.

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