Q147 / 180 · AIIMS 2011 · Physics
Voltage of modulating wave of $5 \mathrm{~V}$ with $10 \mathrm{MHz}$ frequency was superimposed on carrier wave of frequency $20 \mathrm{MHz}$ and voltage $20 \mathrm{~V}$ then the modulation index is
- Correct answerA0.25
- B1.25
- C2.43
- D64.0
Solution
Given, $A_m=5 \mathrm{~V}, A_c=20 \mathrm{~V}$
$\therefore$ Modulation index, $\mu=\frac{A_m}{A_c}=\frac{5}{20}=0.25$
Hence, the correct answer is option: 'A'.