Q145 / 170 · Manipal (MET) 2018 · Physics
Voltage and current in an AC circuit are given by $V=5 \sin \left(100 \pi t-\frac{\pi}{6}\right)$ and $I=4 \sin \left(100 \pi t+\frac{\pi}{6}\right)$
- Avoltage leads the current by $30^{\circ}$
- Bcurrent leads the voltage by $30^{\circ}$
- Correct answerCcurrent leads the voltage by $60^{\circ}$
- Dvoltage leads the current by $60^{\circ}$
Solution
Net phase difference between current and voltage
$=\frac{\pi}{6}-\left(-\frac{\pi}{6}\right)=\frac{\pi}{3}=60^{\circ}$
Hence, current leads the voltage by $60^{\circ}$.
Hence, current leads the voltage by $60^{\circ}$.
Hence, the correct answer is option: 'C'.