Q177 / 200 · Manipal (MET) 2011 · Physics

The time taken by AC of 50 Hz in reaching from zero to the maximum value is

  • A
    $50 \times 10^{-3} \mathrm{~s}$
  • Correct answer
    B
    $5 \times 10^{-3} \mathrm{~s}$
  • C
    $1 \times 10^{-3} \mathrm{~s}$
  • D
    $2 \times 10^{-3} \mathrm{~s}$

Solution

The time taken by AC in reaching from zero to maximum value is $\begin{aligned} t & =\frac{1}{4}=\frac{1}{4 f} \\ & =\frac{1}{50 \times 4}=5 \times 10^{-3} \mathrm{~s}\end{aligned}$

Hence, the correct answer is option: 'B'.

More Alternating Current Questions