Q120 / 200 · AP EAMCET 2001 · Mathematics

Using the digits $0,2,4,6,8$ not more than once in any number, the number of 5 digited numbers that can be formed, is

A
$16$
B
$24$
Correct answer
C
$96$
D
$120$

Solution

The numbers of 5-digits number $={ }^5 P_5$ The numbers begin with $0={ }^4 P_4$ Required numbers $={ }^5 P_5-{ }^4 P_4=120-24=96$

Hence, the correct answer is option: 'C'.

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