$\int \frac{e^{\sin x}(\sin 2 x-8 \cos x)}{2(\sin x-3)^2} d x=$

• A

  $e^{\sin x}(\sin x-3)+c$
• B

  $\frac{e^{\sin x}}{(\sin x-3)^2}+c$
• C

  $e^{\sin x}(\sin x-3)^2+c$
• Correct answer
  D

  $\frac{e^{\sin x}}{\sin x-3}+c$

Hence, the correct answer is option: 'D'.