$\operatorname{Tan}^{-1} \frac{\sqrt{8-2 \sqrt{15}}}{\sqrt{15}+1}+\operatorname{Tan}^{-1} \frac{1}{\sqrt{5}}=$

• Correct answer
  A

  $\frac{\pi}{6}$
• B

  $\frac{\pi}{4}$
• C

  $\frac{\pi}{3}$
• D

  $\frac{\pi}{2}$

Hence, the correct answer is option: 'A'.