Q64 / 160 · AP EAMCET 2025 (26 MAY SHIFT 1) · Mathematics

If $\theta=\operatorname{Tan}^{-1}\left(\frac{1}{3}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{7}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{13}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{21}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{31}\right)$, then $\tan \theta=$

  • A
    $\frac{3}{5}$
  • B
    $1$
  • Correct answer
    C
    $\frac{5}{7}$
  • D
    $\frac{7}{9}$

Hence, the correct answer is option: 'C'.

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