Q64 / 160 · AP EAMCET 2025 (26 MAY SHIFT 1) · Mathematics
If $\theta=\operatorname{Tan}^{-1}\left(\frac{1}{3}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{7}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{13}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{21}\right)+\operatorname{Tan}^{-1}\left(\frac{1}{31}\right)$, then $\tan \theta=$
- A$\frac{3}{5}$
- B$1$
- Correct answerC$\frac{5}{7}$
- D$\frac{7}{9}$
Hence, the correct answer is option: 'C'.