Q16 / 75 · JEE Main 2025 (8 Apr Shift 2) · Chemistry

- Correct answerA$\mathrm{Br}_2 / \mathrm{Fe} ; \mathrm{Cl}_2, \Delta$; alc. KOH
- B$\mathrm{Cl}_2 / \mathrm{Fe} ; \mathrm{Br}_2 /$ anhy. $\mathrm{AlCl}_3 ;$ aq. KOH
- C$\mathrm{Br}_2 /$ anhy. $\mathrm{AlCl}_3 ; \mathrm{Cl}_2, \Delta$; aq. KOH
- D$\mathrm{Cl}_2 /$ anhy. $\mathrm{AlCl}_3 ; \mathrm{Br}_2 / \mathrm{Fe} ;$ alc. KOH
Hence, the correct answer is option: 'A'.