Match the LIST-I with LIST-II
$\begin{array}{|l|l|l|l|}\hline & \text{LIST-I} & & \text{LIST-II} \\ \hline \text{A.} & \text{Carbocation} & \text{I.} & \begin{array}{l} \text{Species that can} \\ \text{supply a pair of} \\ \text{electrons.} \end{array} \\ \hline \text{B.} & \begin{array}{l} \text{C-Free} \\ \text{radical} \end{array} & \text{II.} & \begin{array}{l} \text{Species that can} \\ \text{receive a pair of} \\ \text{electrons.} \end{array} \\ \hline \text{C.} & \text{Nucleophile} & \text{III.} & \begin{array}{l} sp ^2 \text{ hybridized} \\ \text{carbon with empty} \\ \text{p-orbital.} \end{array} \\ \hline \text{D.} & \text{Electrophile} & \text{IV.} & \begin{array}{l} sp ^2 / sp ^3 \text{ hybridized} \\ \text{carbon with one} \\ \text{unpaired electron.} \end{array} \\ \hline \end{array}$
Choose the correct answer from the options given below :

• A

  A-IV, B-II, C-III, D-I
• B

  A-II, B-III, C-I, D-IV
• C

  A-III, B-IV, C-II, D-I
• Correct answer
  D

  A-III, B-IV, C-I, D-II

Hence, the correct answer is option: 'D'.