$\int \frac{\log _e x}{\left(1+\log _e x\right)^2} d x=$

• A

  $-\frac{x}{1+\log _e x}+C$
• B

  $\frac{x}{\left(1+\log _e x\right)^2}+C$
• Correct answer
  C

  $\frac{x}{\left(1+\log _e x\right)}+C$
• D

  $\frac{-x}{\left(1+\log _e x\right)^2}+C$

Hence, the correct answer is option: 'C'.