Q70 / 90 · JEE Main 2023 (31 Jan Shift 2) · Physics

Under the same load, wire A having length 5.0 m and cross section 2.5×10-5 m2 stretches uniformly by the same amount as another wire B of length 6.0 m and a cross section of 3.0×10-5 m2 stretches. The ratio of the Young's modulus of wire A to that of wire B will be:

  • A
    1:4
  • Correct answer
    B
    1:1
  • C
    1:10
  • D
    1:2 

Solution

Elongation in uniform wire under load is given by, Δl=FlSY, where S is area of cross-section.

As F is same for both wire and Δl is also same, we can write

ΔlF=lSY⇒lASAYA=lBSBYB

⇒52.5×10-5×YA=63×10-5×YB

⇒YAYB=1

Hence, the correct answer is option: 'B'.

Relevant Questions