Q18 / 150 · JEE Main 2006 · Chemistry
Uncertainty in the position of an electron (mass $=9.1 \times 10^{-31} \mathrm{~kg}$ ) moving with a velocity $300 \mathrm{~ms}^{-1}$, accurate upto $0.001 \%$, will be
- A$19.2 \times 10^{-2} \mathrm{~m}$
- B$5.76 \times 10^{-2} \mathrm{~m}$
- Correct answerC$1.92 \times 10^{-2} \mathrm{~m}$
- D$3.84 \times 10^{-2} \mathrm{~m}$ (h $\left.=6.63 \times 10^{-34} \mathrm{Js}\right)$
Solution
$$
\begin{aligned}
& \Delta \mathrm{x} . \Delta \mathrm{V} \geq \frac{\mathrm{h}}{4 \pi \mathrm{m}} \\
& \Delta \mathrm{x} \geq \frac{\mathrm{h}}{4 \pi \mathrm{m} \Delta \mathrm{V}}=\frac{6.63 \times 10^{-34}}{4 \times 3.14 \times 9.1 \times 10^{-31} \times 300 \times \frac{0.001}{100}} \\
&=\frac{6.63 \times 10^{-34}}{4 \times 3.14 \times 9.1 \times 3 \times 10^{-31} \times 10^{-3}} \\
&=0.01933 \\
&=1.93 \times 10^{-2}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.