Two waves of same frequency (n) are approaching each other with same velocity of $12 \mathrm{~m} / \mathrm{s}$ along the same linear path and interfere. The distance between two consecutive nodes is

Standing waves form when two waves of identical frequency and amplitude travel in opposite directions, with nodes being points of zero displacement.

The wave relationship $v = n\lambda$ connects velocity, frequency, and wavelength. Given $v = 12$ m/s, the wavelength is $\lambda = \frac{12}{n}$ m.

For standing waves, consecutive nodes are separated by half the wavelength, so the distance is $\frac{\lambda}{2} = \frac{1}{2} \cdot \frac{12}{n} = \frac{6}{n}$ m.

The correct choice is $\frac{6}{n}$.