Q124 / 150 · MHT CET 2026 (19 April Shift 2) · Physics
Two waves of same frequency ($n$) approaching each other with same velocity of $18$ m/s interfere. The distance between two consecutive antinodes is
- A$\dfrac{18}{n}$
- B$\dfrac{10}{n}$
- Correct answerC$\dfrac{9}{n}$
- D$\dfrac{n}{18}$
Solution
Velocity of the waves, $v = 18$ m/s.
Frequency of the waves, $f = n$.
Wavelength of the waves, $\lambda = \dfrac{v}{f} = \dfrac{18}{n}$.
When two identical waves travelling in opposite directions interfere, they form a stationary wave.
The distance between two consecutive antinodes in a stationary wave is $\dfrac{\lambda}{2}$.
Distance = $\dfrac{1}{2} \times \dfrac{18}{n} = \dfrac{9}{n}$.
Frequency of the waves, $f = n$.
Wavelength of the waves, $\lambda = \dfrac{v}{f} = \dfrac{18}{n}$.
When two identical waves travelling in opposite directions interfere, they form a stationary wave.
The distance between two consecutive antinodes in a stationary wave is $\dfrac{\lambda}{2}$.
Distance = $\dfrac{1}{2} \times \dfrac{18}{n} = \dfrac{9}{n}$.
Hence, the correct answer is option: 'C'.