Two particles are executing simple harmonic motion of the same amplitude $\mathrm{A}$ and frequency $\omega$ along the $x$-axis. Their mean position is separated by distance $X_0\left(X_0>A\right)$. If the maximum separation between them is $\left(X_0+A\right)$, the phase difference between their motion is :

• A

  $\frac{\pi}{3}$
• B

  $\frac{\pi}{4}$
• C

  $\frac{\pi}{6}$
• Correct answer
  D

  $\frac{\pi}{2}$

Solution

$\phi_1=0$ $\phi_2=\frac{\pi}{2}$

Hence, the correct answer is option: 'D'.