Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: X12+X12=Y24 The binding energies per nucleon X12 and…

Question

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:

${}_{1}^{2}X + {}_{1}^{2}X = {}_{2}^{4}Y$

The binding energies per nucleon ${}_{1}^{2}X$ and ${}_{2}^{4}Y$ are $1.1 MeV$ and $7.6 MeV$ respectively. The energy released in this process is_____ $MeV$ .

MARKS Content Team · Accepted Answer

Correct answer: 26. Energy released in the given process = Binding energy of product - Binding energy of reactants. =7.6×4-1.1×2×2 =30.4-4.4 =26MeV

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
${}_{1}^{2}X + {}_{1}^{2}X = {}_{2}^{4}Y$
The binding energies per nucleon ${}_{1}^{2}X$ and ${}_{2}^{4}Y$ are $1.1 MeV$ and $7.6 MeV$ respectively. The energy released in this process is_____ $MeV$ .

Solution

Relevant Questions

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: X12+X12=Y24 The binding energies per nucleon X12 and Y24 are 1.1MeV and 7.6MeV respectively. The energy released in this process is_____ MeV.

Solution

Relevant Questions

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
${}_{1}^{2}X + {}_{1}^{2}X = {}_{2}^{4}Y$
The binding energies per nucleon ${}_{1}^{2}X$ and ${}_{2}^{4}Y$ are $1.1 MeV$ and $7.6 MeV$ respectively. The energy released in this process is_____ $MeV$ .