Q22 / 142 · NTA Abhyas (JEE Main) 2020 · Physics · Electrostatics

Two conducting spheres A and B of radius a and b respectively are at the same electric potential. The ratio of the surface charge densities of A and B is

  • Correct answer
    A
    ba
  • B
    ab
  • C
    a2b2
  • D
    b2a2

Solution

Given electric potential of spheres are same i.e.,

VA=VB

14πε0Q1a=14πε0.Q2b 

Q1Q2=ab      

A surface charge density

σ=Q4πr2

⇒σ1σ2=Q1Q2×b2a2

            =ab×b2a2=ba

Hence, the correct answer is option: 'A'.

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