In the given circuit, initially switch ${\mathrm{S}}_1$ is closed and ${\mathrm{S}}_2$ and ${\mathrm{S}}_3$ are open. After charging of the capacitor, at $\mathrm{t}=0$, ${\mathrm{S}}_1$ is open and ${\mathrm{S}}_2$ and ${\mathrm{S}}_3$ are closed. If the relation between inductance, capacitance and resistance is $\mathrm{L}\mathrm{ }=\mathrm{ }4{\mathrm{C}\mathrm{R}}^2$, then find the time (in $\mathrm{s}$) after which the current passing through the capacitor and inductor will be the same. [given $\mathrm{R}=\ln \left(2\right)\mathrm{ }\mathrm{m}\mathrm{\Omega }$, $\mathrm{L}=2\mathrm{ }\mathrm{mH}$]

Hence, the correct answer is 1.