Q143 / 160 · AP EAMCET 2018 (24 Apr Shift 2) · Physics
Two coherent sources $S_1, S_2$ and a screen are arranged as shown in the figure. If the distance between the two coherent sources is $n \lambda$ and the distance of the screen from the nearer coherent source is D, then the distance of the first bright fringe on the screen from the point ' $\mathrm{O}$ ' is
( $\lambda$ is the wavelength of the light emitted by the coherent sources )


- A$\sqrt{\frac{D(D+n \lambda)}{n}}$
- Correct answerB$\sqrt{\frac{2 D(D+n \lambda)}{n}}$
- C$\sqrt{\frac{3 \mathrm{D}(\mathrm{D}+\mathrm{n} \lambda)}{\mathrm{n}}}$
- D$\sqrt{\frac{D(D+n \lambda)}{2 n}}$
Hence, the correct answer is option: 'B'.