The path difference between two waves given by the equations $y_1=a_1 \sin \left(\omega t-\frac{2 \pi x}{\lambda}\right)$ and $y_2=a_2 \sin \left(\omega t-\frac{2 \pi x}{\lambda}+\phi\right)$ is

• A

  $\left(\frac{\lambda}{\pi} \phi\right)$
• B

  $\frac{\lambda}{\pi}\left(\phi-\frac{\pi}{2}\right)$
• Correct answer
  C

  $\frac{\lambda}{2 \pi} \phi$
• D

  $\frac{\lambda}{2 \pi}\left(\phi-\frac{\pi}{2}\right)$

Hence, the correct answer is option: 'C'.