Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volts and…

Question

Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volts and the average resistance per km is 0.5 Ω. The power loss in the wire is:

MARKS Content Team · Accepted Answer

Correct answer: (B) 19.2 kW. Distance between the two cities, 150 km. Voltage drop per kilometre is 8 V km^(-1). Resistance per kilometre 0.5 Ω km^(-1) Total voltage drop will be, V_drop=150 km×8 V km^(-1)=1200 V Total resistance of wire, R=0.5 Ω km^(-1)×150 km=75 Ω Therefore, the power loss will be, P=V^2R=150×8^20.5×150=19.2 kW

Two cities are $150 k m$ apart. Electric power is sent from one city to another city through copper wires. The fall of potential per $k m$ is $8$ volts and the average resistance per $k m$ is $0.5 Ω .$ The power loss in the wire is:

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