Two charges, each equal to $\text{q}$, are kept at $\text{x}=-\text{a}$ and $\text{x} = \text{a}$ on the x-axis. A particle of mass $\text{m}$ and charge ${\text{q}}_0=-\frac{\text{q}}{2}$  is placed at the origin. If charge ${\text{q}}_0$ is given a small displacement $\text{(y << a)}$ along the y-axis, the net force acting on the particle is proportional to :

• A

  $\frac{1}{\text{y}}$
• B

  $-\frac{1}{\text{y}}$
• Correct answer
  C

  $\text{-y}$
• D

  $\text{y}$

Hence, the correct answer is option: 'C'.