Q46 / 46 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In One Dimension

Two cars A and B are moving with a speed of 15 m s-1 and 5 m s-1 and acceleration of the cars are 1 m s-2 and 6 m s-2 respectively. Then the minimum separation between them is
Figure

  • A
    5 m
  • Correct answer
    B
    10 m
  • C
    Zero
  • D
    None

Solution

vAB=10 m s-1, aAB=-5 m s-2
sAB=10t-52t2

Minimum displacement of A w.r.t. B
sABmin is at t=105=2
Minimum separation =20-10=10 m

Hence, the correct answer is option: 'B'.

More Motion In One Dimension Questions