Q32 / 105 · NTA Abhyas (JEE Main) 2020 · Physics · Center of Mass Momentum and Collision

Two blocks A and B of equal mass are released on two sides of a fixed wedge C as shown in the figure. Find the acceleration of the centre of mass of blocks A and B. Neglect friction.

Figure

  • Correct answer
    A
    g2, downwards
  • B
    g, downwards
  • C
    g2, upwards
  • D
    3 4 g , downwards

Solution

Acceleration of both the blocks will be g sin45° or g 2  at right angles to each other. Now,

Figure

a→com=mAa→A+mBa→BmA+mB

Here,    mA = mB

∴    acom=12aA+aB

                     =12g   (downwards)

Hence, the correct answer is option: 'A'.

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